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X^2-9X-8=8
We move all terms to the left:
X^2-9X-8-(8)=0
We add all the numbers together, and all the variables
X^2-9X-16=0
a = 1; b = -9; c = -16;
Δ = b2-4ac
Δ = -92-4·1·(-16)
Δ = 145
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{145}}{2*1}=\frac{9-\sqrt{145}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{145}}{2*1}=\frac{9+\sqrt{145}}{2} $
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